:highfive
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I probably cant even make it to a match becuase of goddamn algebra and having to get ready for sophmore year so goddamn early. Anyway Im not participating. Fuck the deals. But can I vote?
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I AM VOTING
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I have to say, I agree with Sam.
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Hey ZBF solve this:
if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z. NEVER EVER POST IN I-MOCK AGAIN IF YOU FAIL!!!!!!!!!!! actually never ever post in imock again. you have a larger post count than me and that's not healthy. |
The heartbreaking part is that zelda is autistic and will actually try to solve that :<
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man, that makes me feel bad for calling him a moron and all. :(
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I looked at that problem and forgot how to FOIL which kind of sucks because I have math in an hour and a half.
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Enough with the math gibberish. Me no likes.
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if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.
10x^2 + 20xy + 10y^2 ___________________ 2 = 5x^2 + 10xy + 5y^2 = 5 x + y = z -x y = z - x 5x^2 + 10x(x-z) + 5(x-z)^2 = 5 15x^2 - 10xz + 5(x^2 - 2xz + z^2) = 5 TOO MANY FUCKING VARIABLES |
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WHY DOES THE EDIT FUNCTION HAVE TO CRASH FIREFOX ;_;
my point stands |
You can't solve two equations with three unknowns :nerd
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bullshit i can't
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It's like trying to solve one equation with two unknowns (x - y = 6), there's an infinite number of answers.
Emu if we were actually mock warring right now this would probably be pretty close to the real deal :( |
I won't argue math with you dude I respect you too much for that let's drop this grudge and get ourselves a cool mocha okay.
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hey guys is it cool to be in basic math 8)
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if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.
(x^2+2xy+y^2) = (x+y)^2 10((x+y)^2)/2 = 5(x+y)^2 = 5 (x+y)^2 = 1 let u = (x+y) u^2 = 1 u = 1 z = 1 faggots |
50 x 5
??? |
50 50 50 50 50
:picklehat |
golden star for chojin :]
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NEW QUESTION FOR ZELDA:
Prove that every even integer greater than 2 can be written as the sum of two primes. This ones easy guys come on. |
the answer is 420 :lol
smoooke |
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