:highfive

THERE IS YOUR ANSWER MISTER ZERO

I probably cant even make it to a match becuase of goddamn algebra and having to get ready for sophmore year so goddamn early. Anyway Im not participating. Fuck the deals. But can I vote?

I AM VOTING

HAHAHAHAHAHAHAHAHAHA

I have to say, I agree with Sam.

Hey ZBF solve this:
if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.


NEVER EVER POST IN I-MOCK AGAIN IF YOU FAIL!!!!!!!!!!!

actually never ever post in imock again. you have a larger post count than me and that's not healthy.

The heartbreaking part is that zelda is autistic and will actually try to solve that :<

man, that makes me feel bad for calling him a moron and all. :(

I looked at that problem and forgot how to FOIL which kind of sucks because I have math in an hour and a half.

Enough with the math gibberish. Me no likes.

if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.

10x^2 + 20xy + 10y^2
___________________
2

=

5x^2 + 10xy + 5y^2 = 5

x + y = z
-x
y = z - x

5x^2 + 10x(x-z) + 5(x-z)^2 = 5

15x^2 - 10xz + 5(x^2 - 2xz + z^2) = 5

TOO MANY FUCKING VARIABLES

WHY DOES THE EDIT FUNCTION HAVE TO CRASH FIREFOX ;_;

my point stands

You can't solve two equations with three unknowns :nerd

bullshit i can't

It's like trying to solve one equation with two unknowns (x - y = 6), there's an infinite number of answers.

Emu if we were actually mock warring right now this would probably be pretty close to the real deal :(

I won't argue math with you dude I respect you too much for that let's drop this grudge and get ourselves a cool mocha okay.

hey guys is it cool to be in basic math 8)

if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.

(x^2+2xy+y^2) = (x+y)^2

10((x+y)^2)/2 = 5(x+y)^2 = 5

(x+y)^2 = 1

let u = (x+y)

u^2 = 1

u = 1

z = 1

faggots

50 x 5

???

50 50 50 50 50

:picklehat

golden star for chojin :]

NEW QUESTION FOR ZELDA:

Prove that every even integer greater than 2 can be written as the sum of two primes.

This ones easy guys come on.

the answer is 420 :lol

smoooke