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Level 29 ♂
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Join Date: Aug 2003
Location: Peoria, IL
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Jan 31st, 2007, 11:58 AM
if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.
10x^2 + 20xy + 10y^2
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2
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5x^2 + 10xy + 5y^2 = 5
x + y = z
-x
y = z - x
5x^2 + 10x(x-z) + 5(x-z)^2 = 5
15x^2 - 10xz + 5(x^2 - 2xz + z^2) = 5
TOO MANY FUCKING VARIABLES
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Last edited by Emu : Jan 31st, 2007 at 11:59 AM.
Reason: i think that should be subtraction
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