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Emu Emu is offline
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Old Jan 31st, 2007, 10:58 AM       
if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.

10x^2 + 20xy + 10y^2
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2

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5x^2 + 10xy + 5y^2 = 5

x + y = z
-x
y = z - x

5x^2 + 10x(x-z) + 5(x-z)^2 = 5

15x^2 - 10xz + 5(x^2 - 2xz + z^2) = 5

TOO MANY FUCKING VARIABLES

Last edited by Emu : Jan 31st, 2007 at 10:59 AM. Reason: i think that should be subtraction
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