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CaptainBubba CaptainBubba is offline
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Old Jan 31st, 2007, 03:03 PM       
if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.

(x^2+2xy+y^2) = (x+y)^2

10((x+y)^2)/2 = 5(x+y)^2 = 5

(x+y)^2 = 1

let u = (x+y)

u^2 = 1

u = 1

z = 1

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