[Tropical]

Originally Posted by CaptainBubba

if 10(x^2+2xy+y^2)/2=5 and x+y=z then find z.

(x^2+2xy+y^2) = (x+y)^2

10((x+y)^2)/2 = 5(x+y)^2 = 5

(x+y)^2 = 1

let u = (x+y)

u^2 = 1

u = 1

z = 1

faggots

actually you're only half right

z= 1 or -1